Question 424631
You will get two answers for this problem!
{{{n^2+4n = 12}}}"...if the square of that number (n) is increased by 4 times the number, the result is 12."
Subtract 12 from both sides.
{{{n^2+4n-12 = 0}}} Factor this quadratic equation.
{{{(n-2)(n+6) = 0}}} Apply the zero product rule.
{{{n-2 = 0}}} or {{{n+6 = 0}}} then...
{{{n = 2}}} or {{{n = -6}}}
The two numbers are 2 and -6