Question 424620
{{{drawing(200,200,0,10,0,10,


triangle(3,1,8,1,8,1+5sqrt(3)),
locate(4,2,2x),
locate(7.5,5sqrt(3), x)


)
}}}


Almost more like an algebra problem. We can call the larger acute angle 2x and the smaller x. The sum of those two angles, plus the 90 degree angle, is 180, so


2x + x + 90 = 180

3x = 90

x = 30, so the angles are 30 and 60.