Question 424560
Let one number is {{{x}}}. Then another number is {{{x-4}}}. 
Then:
{{{x^2 - (x-4)^2 = 80}}}
{{{x^2 - (x^2 - 8x + 16) = 80}}}
Simplify this equation:
{{{x^2 - x^2 + 8x - 16 = 80}}}
{{{8x - 16 = 80}}}
{{{8x = 96}}}
{{{x = 96/8 = 12}}}
Then {{{x-4 = 12-4 = 8}}}.

Answer: one number is 12 and another number is 8.