Question 424505

a) no. of ways = 5C4 = 5


b) no. of ways = 5C2 * 4C2 = 10 * 6 = 60


c) no. of ways = 5C1 * 3C1 * 2C2 = 5 * 3 * 1  = 15


d) no. of ways = 4C4 = 1