Question 44711
This is what I came up with. What am I doing wrong?
b^2 - 3b = 5

You had b^2-3b+(3/2)^2= 5+(3/2)^2

You factored to get:
(b+(3/2))^2 = 5+(3/2)^2

You should have gotten:
(b-(3/2))^2 = 5+(3/2)^2

Cheers,
Stan H.