Question 424435
Solve:logax+loga(x-2)=loga3

      loga x(x-2)=loga 3

        x(x-2)=3

     {{{x^2-2x-3=0}}} is a quadratic equation, which can be written:

      {{{(x+1)*(x-3)=0}}}

x+1=0 => x=-1 and x-3=0 => x=3 The roots are {-1, 3}

Since the logarithm of negative numbers doesn't exist the value x=-1 is rejected.

  Answer.The solution set is {x: x=3}