Question 424352
i have to find all real solution to equation 5(b-1)^2-4=221 and also i don't know how to apply quadratic formula to this equation.
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5(b-1)^2-4=221 
5(b-1)^2 = 225
(b-1)^2 = 45
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(b-1) = +-sqrt(9*5)
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b-1 = +-3sqrt(5)
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b = 1+3sqrt(5) or b = 1-3sqrt(5)
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Cheers,
Stan H.
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