Question 5772
{{{(-y)^(5)m^(8)/y^(3)m^(-7)}}}


first things first...-1 to power 5 is -1*-1*-1*-1*-1 which is -1.

y^5/y^3...division, so subtract powers --> y^2
m^8/m^(-7)...division, so subtract powers --> 8-(-7) -> 8+7 --> 15


so, answer is {{{-y^2m^15}}}


jon.