Question 424135


{{{a = -4}}}

{{{ b=-6}}} and 

{{{c=4}}} 


{{{a^3+b^2-c^4/b^0}}}

= {{{(-4)^3 + (-6)^2 - 4^4/(-6)^0}}}


= {{{(-4)(-4)(-4) + (-6)(-6) - 256/1}}}


= {{{-64 + 36 - 256/1}}}


= {{{-28 - 256}}}


= {{{-284}}}