Question 424112
When the given function is in the form:{{{a(x-h)^2+k}}}, the axis of symmetry is given by: {{{x = h}}}, so...
{{{h(x) = -4(x+6)^2+7}}} you have: a = -4, h = -6, and k = 7.
The axis of symmetry here is:
{{{x = -6}}}