Question 424085
Height and Weight 
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Suppose that the weight of a
person is directly proportional to the cube of the
person’s height.
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W = k*H^3
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If one person weighs twice as much
as a (similarly proportioned) second person, by what
factor is the heavier person’s height greater than the
shorter person’s height?
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Let the 2nd person's weight be "x"
x = k*H^3
H = [x/k]^(1/3) (2nd person's height)
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The 1st person's weight is "2x"
2x = kH^3
H = [2x/k]^(1/3)
H = 2^(1/3)[x/k]^(1/3) (1st person's height)
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By what factor is the heavier person’s height greater than the
shorter person’s height?
Answer: 2^(1/3)
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Cheers,
Stan H.
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