Question 424068
10x-6y	=-11		
Find the slope of this line 								
								
6y=10x+11		
Divide by 6							
y=1 2/3	x +1.83		
Compare this equation with y=mx+b								
slope m =	5/3							
								
The slope of a line perpendicular to the above line will be the negative reciprocal								
m1*m2=-1								
The slope of the required line will be 			- 3/5			- 3/5	=	-0.60
								
m=	-0.60	,point	(-5,-8)	
Find b by plugging the values of m & the point in								
y=mx+b								
-8=3+b				
b=-11							
m=- 3/5							
The required equation is	y=-0.6x	-11