Question 423619
I assume the 10's are the bases of the logarithm:
{{{log(10, (y)) - log(10, (2-y)) = 0}}}
The quick way to solve this is to add the second logarithm to each side:
{{{log(10, (y)) = log(10, (2-y))}}}
The only way for these two base 10 logarithms to be the same is if the arguments are the same , too:
y = 2-y
Adding y to each side:
2y = 2
Dividing by 2:
y = 1