Question 423993
3+log2(x-3)=log2 4x
-----
log2(4x)-log2(x-3) = 3
----
log2[(4x)/(x-3)] = 3
----
4x/x-3 = 2^3
----
4x = 8(x-3)
4x-8x= -24
-4x = -24
x = 6
============
Cheers,
Stan H.
============