Question 423933
log(x)+log(2x)=2
log(x)(2x)=2
log(2x^2)=2 
let both sides be the exponent of base 10
10^log(2x^2)=10^2
exponent is release
2x^2=10^2
divide by 2
2x^2/2=100/2
x^2=100/2
square root both sides
x=+- sqrt50