Question 423775
Solution: -3, -2, 3 are all real zeros  for this polynomial,thus we can divide it by (x+3), (x-3)and (x+2)

{{{(x^3+2x^2-9x-18)/(x+3)=(x^2-x-6)=(x+2)*(x-3)}}} Finally we have:

{{{x^3+2x^2-9x-18=(x+2)*(x+3)*(x-3)}}}