Question 44674
{{{2x^2+45=x^2+14x}}}
Rearrange to get zero on the right-hand side:
{{{x^2+45=14x}}}
{{{x^2-14x+45=0}}}
Now you have a quadratic expression, which can be solved using the quadratic solver {{{x = (-b +- sqrt( b^2-4ac ))/(2a) }}} where
a=1
b=-14
c=45.
Plug these values into the solver to get:
{{{x = (14 +- sqrt( 14^2-4(45) ))/2 }}}
{{{x = (14 +- sqrt( 14^2-180 ))/2 }}}
{{{x = (14 +- sqrt( 196-180 ))/2 }}}
{{{x = (14 +- sqrt( 16 ))/2 }}}
{{{x = (14 +- 4)/2 }}}
{{{x = 7 +- 2 }}}
so the two solutions are x=5 or x=9.

I hope this helps.
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
Adam