Question 423803
We have 48Q and 21D.  The total number of coins in the jar = 69.
The total value of the coins = $0.20 means we need the probability of selecting two dimes.  For the first draw the probability of selecting a dime = 21/69 since there are 21 dimes and 69 total coins.  For the 2nd draw, since the first dime wasn't replaced, there are 20 dimes remaining and 68 total coins.  Therefore, the probability of selecting a dime = 20/68.  
The probability of selecting two dimes is the product of these: P(2 dimes) = (21/69)*(20/68) = 0.0895