Question 423391
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Hi
 {{{P[t] = P[0]e^rt}}} where r is the rate of decay and t the number of hours

 Question states***
   8262/6000 = e^8r
ln(8262/6000) = .3199 = 8r
     .3199 = 8r
       .04 = r
 {{{P[24] = 6000e^(.04*24)}}} = 15,670 present after 24 hours