Question 423368
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Hi
Solving
x^2/3-7x^1/3+6=0
Let a = {{{root(3,x)}}}
 a^2 -7a+ 6 =  0
 factoring
(a-6)(a-1) = 0
 (a-6)= 0   a = 6    x = 216  (x = a^3)
 (a-1)= 0   a = 1    x = 1

CHECKING our Answer***
 1 - 7 + 6 = 0
 36 - 42 + 6 = 0