Question 423266

no. of ways to select 3 books from 9 books = 9C3 = 84


a) no. of ways to select 1 dictionary and 2 other books =8C2* 1C1 = 28

required probability = 28/84 

= 1/3

b) no. of ways to select 2 novels and 1 poem book = 5C2 * 3C1 = 10 * 3 = 30


required probability = 30/84

= 5/14