Question 423152
{{{ log(4x) = log(5) + log(x-4) }}}
{{{ log(4x) = log (5*(x-4)) }}}
The logs are equal, so
{{{ 4x = 5x - 20 }}}
{{{ x = 20 }}}
check answer:
{{{ log(4x)=log(5)+log(x-4) }}}
{{{ log(80) = log(5) + log(20 - 4) }}}
{{{ log(80) = log(5*16) }}}
{{{ log(80) = log(80) }}}
OK