Question 422912


{{{b^4-3b^3-10b^2}}}.....factor out common term {{{b^2}}}

{{{b^2(b^2-3b-10)}}}......now factor {{{(b^2-3b-10)}}}.....replace {{{-3b}}} with {{{2b -5b}}}

{{{b^2(b^2 + 2b -5b-10)}}}....group first two and second two terms

{{{b^2((b^2 + 2b) -(5b+10))}}}......factor out{{{b}}} from {{{(b^2 + 2b)}}} and 

{{{5}}} from {{{(5b+10)}}}

{{{b^2(b(b + 2) -5(b+2))}}}

{{{b^2(b-5)(b+2))}}}