Question 422975
{{{y=sqrt(x)+z^2}}}



{{{y-z^2=sqrt(x)}}}



{{{(y-z^2)^2=x}}}



{{{x=(y-z^2)^2}}}



{{{x=y^2-2yz^2+z^4}}}



So {{{x=y^2-2yz^2+z^4}}}



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