Question 422941
Let x3 be y
y2-65y+64=0
y^2-64y-y+64=0
y(y-64)-1(y-64)=0
(y-1)(y-64)=0

solutions  y-1=0 or y=1 or X^3=1 or x=1
y-64=0
y=64
x^3=64
x=4

Note  because it is cube , you do not have + and - 
The sign remains the same