Question 422870

no. of ways to arrange these 6 digits = 6! 


no. of ways to arrange 6 digits where first and last digit are even 

= no. of ways to arrange first and last digit * no. of ways to arrange 4 inner digits

= 2! * 4!

= 2 * 24

= 48


required probability = 48/6! 

= 48/720

= 1/15