<PRE><B>Question 422285</B>
solve for x : log5(10x+4) - log5(2) = 1/2log5(49) + 2log5(4)
:
1/2 is the square root exponent, return the exponent to inside the radical
{{{log5((10x+4)/2) = log5(sqrt(49)) + log5(4^2)}}}
Which is
log5(5x+2) = log5(7) + log(16)
:
log5(5x+2) = log5(7*16)
log5(5x+2) = log5(112)
:
therefore, we can say:
5x + 2 = 112
5x = 112 - 2
5x = 110
x = {{{110/5}}}
x = 22
;
:
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