Question 422607

{{{x^2-9=0}}}

{{{x^2-3^2=0}}}...factor as the difference of the squares

{{{(x-3)(x+3)=0}}}

if {{{x-3=0}}}.....->...{{{x=3}}}

if {{{x+3=0}}}.....->...{{{x=-3}}}

so, your solutions are: {{{x1=3}}} and {{{x2=-3}}}