Question 422595
I'm really confused right now on this problem;
6x^2-12x+1=0

This is what I have done so far,
{{{ x=-(-12)+ sqrt(-12^2-4(6)(1))/2(6) }}}
{{{ x=12+ sqrt (144-24)/12 }}} 
{{{ x=12+ sqrt (120)/12 }}}
x=12+ sqrt 12+?/12 <-- The part I'm stuck on

I know I'm almost done and that the answer won't be a nice perfect number
And I used the equation solver thing, but the answer won't help unless I understand how it got there, xD 

Anyways
Sorry if I didn't write the formula right,
Thanks in advance too. ^^ 
<pre><font face = "consolas" color = "indigo" size = 4><b>

The quadratic formula is

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

not this

{{{cross(x = -b + sqrt( b^2-4*a*c )/(2*a)) }}}

The other tutor used this form too, and that's wrong because 
the -b term must also be on top of the fraction bar.  Also
there must be a double sign ±, not just +.

The first three steps should be

{{{ x=(-(-12) +- sqrt((-12)^2-4(6)(1)))/2(6) }}}
{{{ x=(12 +- sqrt (144-24))/12 }}} 
{{{ x=(12 +- sqrt (120))/12 }}}

and then:

{{{ x=(12 +- sqrt (4*30))/12 }}}
{{{ x=(12 +- 2sqrt (30))/12 }}}
{{{ x=(2(6 +- sqrt (30)))/12 }}}
{{{ x=(6 +- sqrt (30))/6 }}}

Edwin</pre>