Question 422167
No, you can't do that, this is a toughie
{{{x^2+x+(sqrt(x^2+x))- 2 = 0}}} 
:
{{{x^2 + x- 2}}} = -{{{sqrt(x^2+x)}}}
Square both sides
{{{(x^2 + x- 2)^2}}} = {{{x^2 + x}}}
FOIL the left
{{{x^4+2x^3-3x^2-4x+4}}} = {{{x^2 + x}}}
combine on the left
{{{x^4+2x^3-3x^2-x^2-4x-x+4}}} = 0
{{{x^4+2x^3-4x^2-5x+4}}} = 0
What can you do with this? it won't factor, graph the original and the above equation, see what we have
{{{ graph( 300, 200, -4, 4, -4, 4, x^2+x+sqrt(x^2+x)-2, x^4+2x^3-4x^2-5x+4 ) }}}
find the x intercepts, -1.6, and + .62 (not exact) Correction!!
:
Check both values in the original equation, see if it works