Question 422335
find the center of this ellipse: 
16x^2+4y^2+64x+24y+36 = 0
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16(x^2+4x+4) + 4(y^2+6y+9) = -36+16*4+4*9
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16(x+2)^2 + 4(y+3) = 24
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Center at (-2,-3)
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Cheers,
Stan H.
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