Question 422273
First write equations for what you know:  A perimeter is the distance around the rectangle, there are 2 lengths and 2 widths, we know the perimeter is 58 inches..So...

2L + 2W = 58  this is equation 1

Next we know that the length is one more than 3 times the width..so..

L = 3W + 1 equation 2

Since we know that L = 3W + 1 we can substitute the L in equation 1

2(3W + 1) + 2W = 58   solve the problem
6W + 2 + 2W = 58     add the common terms
8W + 2 = 58      subtract 2 from both sides
8W = 56          divide by 8
W = 7

Now that you know W, go back and solve for L....use equation 2

L = 3(7) + 1
L + 21 + 1
L = 22

hope this helps