Question 422248
"How do I solve
 2a/a^2-9 + a/a-3 "


2a/a^2 - 9 + a/a - 3
= 2a/(a + 3)(a - 3) + a/a - 3 {factored a^2 - 9, it is a difference of two squares}
= 2a/(a + 3)(a - 3) + a(a + 3)/(a + 3)(a - 3) {got a common denominator of (a + 3)(a - 3)}



2a + a(a + 3)
-------------- {wrote vertically to see better}
(a + 3)(a - 3)


2a + a^2 + 3a
------------- {used distributive property}
(a + 3)(a - 3)


a^2 + 5a
-------------- {combined like terms}
(a + 3)(a - 3)
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