<PRE><B>Question 422161</B>
I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base of the triangle
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Area = (1/2)(base)*(height)
44 = (1/2)(x)(x+3)
22 = x^2+3x
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x^2+3x-22 = 0
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x = [-3 +- sqrt(9-4*-22)]/2
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x = [-3 +- sqrt(97)]/2
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Positive Solution:
x = [-3+sqrt(97)]/2 (base)
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x = [-3+sqrt(97) +6]/2
x = [3+sqrt(97)]/2 (height)
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Cheers,
Stan H.
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