Question 421882
A projectile is shot up from a below-ground trench, so that its position 
relative to ground level at t seconds is y=f(t)=-11+120t-16t^2 feet
:
a) find the position of the projectile relative to ground level at t=0.
t=0
f(0) = -11 + 120(0) - 16(0^2)
f(0 = -11, (11 ft below ground level at t=0)
:
b) sketch graph of f(t). give coordinates of the highest point, and all intercepts.
enter: y = -16x^2+120x-11, on your graphing calc, results:
{{{ graph( 300, 200, -4, 10, -50, 300, -16x^2+120x-11) }}}

c)what is the highest position of the projectile?
d) Does the projectile ever reach 189 feet above ground level?