Question 422054
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Hi
f(x) = x^2 - 1 and g(x) = x + 3 
You most likely are familiar with f(2) = 2^2 - 1.
 f(g(x)) works the same way...
only one substitutes (x+3) for x in the f(x) function
 f(g(x))= f(x+3) = (x+3)^2 - 1 = x^2 + 6x + 9 -1 = {{{x^2 + 6x + 8}}}