Question 421411
{{{root(3, 125^8)/root(3, y^3)}}}
A fact about radicals that will help us with this problem is
{{{root(p, a^q) = (root(p, a))^q}}}
This helps us because {{{5^3 = 125}}} so {{{root(3, 125) = 5}}}. So if we can find the cube root before we raise to the 8th power, it will be easier:
{{{(root(3, 125))^8/root(3, y^3)}}}
The two cube roots simplify giving us:
{{{5^8/y}}}
This may be an acceptable form for the answer. If not, then get out your calculator and figure out {{{5^8}}}.