Question 421955

It is given that {{{-2}}} is one of the roots {{{x}}} of the quadratic equation 


{{{x=-2}}}

{{{h-8x-2x^2=0}}}........plug in {{{x=-2}}} and solve for {{{h}}}

{{{h-8(-2)-2(-2)^2=0}}}

{{{h+16-2(4)=0}}}

{{{h+16-8=0}}}

{{{h+8=0}}}

{{{h=-8}}}