Question 421936
2x^2+8x-h=0  we know 2 is a root  we can divide by x-2

2x^2+8x-h
----------
x-2}

x-2){2x^2+8x-h} -------2x+4
      2x^2-4x
      ---------  
           4x-h 
           4x-8
           -----  

for the result to be 0 h has to be 8