Question 421872

  We can make some transformations at initial equation: {{{y^2=x^2-4x+3}}}

   Add {{{4-y^2}}} on both sides of equation.{{{y^2+4-y^2=x^2-4x+3+4-y^2}}}

   {{{(x-2)^2-y^2=1}}} The final equation is the equation of hyperbola with center

the point (2,0).