<PRE><B>Question 421802</B>
An ice hockey rink is a rectangle with a perimeter of 174 meters. The length is 9 meters more than twice the width. Find the length and width?
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Perimeter = 2(width + length)
Let width = x
Then length = 2x+9
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174 = 2(x + 2x+9)
87 = 3x+9
3x = 78
x = 26
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Width = 26 meters
Length = 2x+9 = 52+9 = 61 meters
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Cheers,
Stan H.
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