Question 421799
Solutions: Let the three consecutive odd integers are x,x+2 and x+4

Given sum of the three is 111

x+(x+2)+(x+4)=111
3x+6=111
3x=111-6
3x=105
x=105/3
x=35

Therefore the three consecutive odd integers are x=35
x+2=35+2=37
x+4=35+4=39

The product of the smallest and the largest integers are 35x 39=1365