Question 421661


{{{n^2+5n+6= (n+3)}}}....replace {{{5n}}} with {{{2n+3n}}}

{{{n^2+2n+3n+6= (n+3)}}}


{{{(n^2+2n)+(3n+6)= (n+3)}}}


{{{n(n+2)+3(n+2)= (n+3)}}}


{{{(n+3)(n+2)= (n+3)}}}........divide both sides by {{{n+3}}}


{{{(n+3)(n+2)/(n+3)= (n+3)/(n+3)}}}..reduce


{{{cross((n+3))(n+2)/cross((n+3))= cross((n+3))1/cross((n+3))1}}}

{{{(n+2)= 1}}}