<PRE><B>Question 421542</B>
The owner of an appliance store uses a normal distribution with mean 10 and variance 9 to model the weekly net sales (in units of $1000). The owner needs $3500 a week to pay his staff. Determine the probability that the weekly net sales will not be enough to pay the whole of this amount. 
-------
z(3500) = (3.5-10)/9 = -0.7778
-----
P(x &lt; 3.5 thousand) = P(z &lt; -0.7778) = 0.2184
-----
============
Cheers,
Stan H.
============
</PRE>