Question 421439
{{{((2x^2 - 10x)/ (x^2 +8x +16))}}} * {{{((4x + 16)/ (x^2 - 25))}}}
: 
we can do a lot of factoring here, one denominator is a perfect square, one is the difference of squares
{{{(2x(x - 5))/ ((x+4)(x+4))}}} * {{{(4(x + 4))/ ((x-5)(x+5))}}}
:
Cancel x-5 and x+4, results:
{{{(2x)/ ((x+4))}}} * {{{4/ ((x+5))}}} 
:
{{{(2x)/ ((x+4))}}} * {{{4/ ((x+5))}}} = {{{(8x)/(x+4)(x+5))}}}