Question 421276
{{{16(x+2)-8=16x+24}}}
{{{16x + 32 - 8 = 16x + 24}}}
subtract {{{16x}}} from both sides
{{{ 32 - 8 = 24}}}
{{{ 24 = 24}}}
This is what is called an identity. There are  an
infinite number of values you can choose for
{{{x}}} and the equation will still be true.
It is true for {{{x = 439100319007}}} and
also for {{{x = -.1000006155532}}}, for 
example