Question 421143
In skeet shooting, the clay pigeon is launched from a height of 4 feet and reaches a maximum height of 164 feet at a distance of 80 feet from the launch site.
a) write an equation for the height of the clay pigeon in terms of the horizontal distance it has traveled? 
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h(t) = -16t^2+vot+ho
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164 ft = -16*80 + vo*80 + 4
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164 = -1280 + 80vo + 4
80vo = 160+1280
80vo = 1440
vo = 18 ft/sec
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Equation:
h(t) = -16t^2+18t+4
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Cheers,
Stan H.
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