Question 421146
A set of 50 data values has a mean of 39 and a variance of 9.
Note: standard deviation = sqrt(9) = 3
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I. Find the standard score (z) for a data value = 43.
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z(43) = (43-39)/3 = 4/3
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II. Find the probability of a data value < 43.
P(x < 43) = P(z < 4/3) = normalcdf(-100,43) = 0.9088
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Cheers,
Stan H.
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