Question 421154
the equation of the axis of the parabola x^2-4y+8=0
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4y = x^2+8
y = (1/4)x^2 + 8
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Vertex at (0,8)
Axis of symmetry: x = 0
{{{graph(400,300,-10,10,-5,20,(1/4)x^2+8)}}}
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Cheers,
Stan H.
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