Question 420784
In order to use log(3) and log(5) to find log(5/3) you have to express log(5/3) in terms of log(3) and/or log(5).<br>
Fortunately a property of logarithms, {{{log(a, (p/q)) = log(a, (p)) - log(a, (q))}}}, shows us how to express the log of a quotient in terns of the logs of its numerator and denominator. Using this property on log(5/3) we get:
log(5) - log(3)
Now we can replace these logs with the values you were given:
0.699 - 0.477
which simplifies to:
0.222
So log(5/3) = 0.222